Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
The HCF of two numbers is 12 and their product is 2160. Find their LCM.
120
150
180
200
180
Since the product of two numbers is always divisible by their HCF, simply divide the product by the HCF: 2160├╖12=180.
HCF of two numbers is 12, Product of the two numbers is 2160.
LCM┬аimes┬аHCF=extProductoftwonumbers
Since the product of two numbers is always divisible by their HCF, simply divide the product by the HCF: 2160├╖12=180.
Students often confuse the product of numbers with the sum of numbers or incorrectly divide the product by the HCF twice.
Identify the relationship
The fundamental property relating two numbers a and b to their HCF and LCM is aimesb=LCMimesHCF.
LCM┬аimes┬аHCF=extProduct
Substitute given values
Substitute HCF=12 and Product=2160 into the formula: LCMimes12=2160.
LCMimes12=2160
Solve for LCM
Divide 2160 by 12 to find the LCM: LCM=122160тАЛ=180.
LCM=122160тАЛ=180
C is correct because dividing the product 2160 by the HCF 12 yields the LCM value of 180.
This concept of Product=LCMimesHCF is frequently tested in Number Systems and is essential for solving problems involving ratios of two numbers.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants