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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ElectricalBasic Electrical
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The resistance of a 100 W, 200 V lamp is

A

100 ohm

B

200 ohm

C

400 ohm

D

1600 ohm

Correct Answer

⚙️ TE • Technical Direct FormulaElectricalBasic Electrical
Option C

400 ohm

Quick Summary:

Given: Power of the lamp P = 100 W, Voltage rating V = 200 V

📐MAMath SolutionDirect Formula
📋 Given

Power of the lamp P = 100 W, Voltage rating V = 200 V

🔢 Formula Used

R=V2PR = \frac{V^2}{P}R=PV2​

🔢 Step-by-Step Solution
1

Identify the relevant formula

The relationship between power PPP, voltage VVV, and resistance RRR for an electrical appliance is given by the formula P=V2RP = \frac{V^2}{R}P=RV2​. We need to calculate RRR.

R=V2PR = \frac{V^2}{P}R=PV2​

2

Substitute the given values

Substitute the given values into the rearranged formula: V=200V = 200V=200 V and P=100P = 100P=100 W.

R=200°2100R = \frac{200°2}{100}R=100200°2​

3

Calculate the final resistance

Perform the arithmetic: 200°2=40,000200°2 = 40,000200°2=40,000. Then, 40,000/100=40040,000 / 100 = 40040,000/100=400.

R=40000100=400 ΩR = \frac{40000}{100} = 400 \ \OmegaR=10040000​=400 Ω

✅

C is correct because using the relation R=V2/PR = V^2 / PR=V2/P, we find R=(200)2/100=400 ΩR = (200)^2 / 100 = 400 \ \OmegaR=(200)2/100=400 Ω.

Core Concepts Used
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Ohm's Law Electrical Power DC Circuits
💡 EXAM TIP

In AC circuits, this calculated resistance is often called the 'hot resistance' of the lamp, which is significantly higher than the resistance measured at room temperature due to the temperature coefficient of the tungsten filament.

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