The r.m.s. value of a sine wave is 100 A. Its peak value is

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Examoogle · Accepted Answer

141.4 A

Explanation: Given: Root mean square (r.m.s.) value of the sine wave I_rms = 100 A

Formula Used: $$I_{peak} = I_{rms} 	imes \sqrt{2}$$

Steps: Identify the relationship between peak and RMS values: For a sinusoidal wave, the relationship between the root mean square value ($I_{rms}$) and the peak value ($I_{peak}$) is defined by the constant factor $\sqrt{2}$.. Substitute the given values: Given $I_{rms} = 100	ext{ A}$ and using $\sqrt{2} \approx 1.414$, substitute these into the formula.. Calculate the final result: Multiplying the values gives the peak current.

Answer: B is correct because the peak value of a sine wave is $\sqrt{2}$ times its r.m.s. value, which results in $100 	imes 1.414 = 141.4	ext{ A}$.

Exam Tip: In AC circuits, remember that for a sine wave, the Average value is $0.637 	imes I_{peak}$ and the Form Factor is $1.11$, which is the ratio of $I_{rms}$ to $I_{avg}$.

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