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The sides of a triangle are 13 cm, 14 cm, and 15 cm. What is the area of the triangle?
84 sq cm
90 sq cm
96 sq cm
105 sq cm
84 sq cm
Memorize the area of the 13-14-15 triangle as a standard result, as it is a common pattern in competitive exams. Alternatively, split the triangle into two right-angled triangles with a height dropped to the base 14, yielding heights of 12 and base segments of 5 and 9.
The lengths of the sides of a triangle are a = 13 cm, b = 14 cm, and c = 15 cm.
Area=s(sтИТa)(sтИТb)(sтИТc)тАЛ┬аwhere┬аs=2a+b+cтАЛ
Memorize the area of the 13-14-15 triangle as a standard result, as it is a common pattern in competitive exams. Alternatively, split the triangle into two right-angled triangles with a height dropped to the base 14, yielding heights of 12 and base segments of 5 and 9.
Students often calculate the semi-perimeter s correctly as 21 but make arithmetic errors in the subtraction (sтИТa), (sтИТb), or (sтИТc) under the square root.
Calculate the semi-perimeter
Calculate the semi-perimeter s using the formula s=2a+b+cтАЛ.
s=213+14+15тАЛ=242тАЛ=21┬аcm
Calculate the area using Heron's formula
Substitute the values of s, a, b, and c into the area formula.
Area=21(21тИТ13)(21тИТ14)(21тИТ15)тАЛ
Simplify the expression
Perform the subtractions and multiply the factors.
Area=21├Ч8├Ч7├Ч6тАЛ=(3├Ч7)├Ч(23)├Ч7├Ч(2├Ч3)тАЛ
Final Calculation
Group the prime factors to extract the square root.
Area=24├Ч32├Ч72тАЛ=22├Ч3├Ч7=4├Ч21=84┬аsq┬аcm
A is correct because the application of Heron's formula yields a final area of 84 sq cm.
This specific 13-14-15 triangle is frequently used in coordinate geometry to test distance formula concepts or in trigonometry to find sin(A) using the area formula Area=21тАЛbcsin(A).