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ElectricalPower System
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The zero sequence current of a generator for line to ground fault is j2.4 pu. Then the current through the neutral during the fault is

A

j2.4 puj2.4\text{ pu}j2.4 pu

B

j0.8 puj0.8\text{ pu}j0.8 pu

C

j7.2 puj7.2\text{ pu}j7.2 pu

D

j0.24 puj0.24\text{ pu}j0.24 pu

Correct Answer

⚙️ TE • Technical Direct FormulaElectricalPower System
Option C

j7.2 puj7.2\text{ pu}j7.2 pu

Quick Summary:

Given: Zero sequence current of the generator I0I_{0}I0​ = j2.4 pu

📐MAMath SolutionDirect Formula
📋 Given

Zero sequence current of the generator I0I_{0}I0​ = j2.4 pu

🔢 Formula Used

In=3×I0I_n = 3 \times I_0In​=3×I0​

🔢 Step-by-Step Solution
1

Identify the relationship

In a three-phase system, the current flowing through the neutral (InI_nIn​) during an unsymmetrical fault is the sum of the sequence currents of the three phases.

In=Ia+Ib+IcI_n = I_a + I_b + I_cIn​=Ia​+Ib​+Ic​

2

Apply Sequence Component theory

The zero sequence current is defined as I0=13(Ia+Ib+Ic)I_0 = \frac{1}{3}(I_a + I_b + I_c)I0​=31​(Ia​+Ib​+Ic​). Therefore, the total neutral current is equal to three times the zero sequence current.

In=3×I0I_n = 3 \times I_0In​=3×I0​

3

Calculate the result

Given the zero sequence current I0=j2.4 puI_0 = j2.4\text{ pu}I0​=j2.4 pu, substitute this value into the formula to find the neutral current.

In=3×(j2.4)=j7.2 puI_n = 3 \times (j2.4) = j7.2\text{ pu}In​=3×(j2.4)=j7.2 pu

✅

C is correct because the neutral current is defined as three times the zero sequence current, resulting in j7.2 puj7.2\text{ pu}j7.2 pu.

Core Concepts Used
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Symmetrical Components Zero Sequence Current Neutral Current Unsymmetrical Fault Analysis
💡 EXAM TIP

This concept is vital for designing grounding schemes; note that the neutral current is zero in balanced systems but becomes significant during single-line-to-ground faults.

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