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Two numbers are in the ratio 5 : 8. If the first number is increased by 13 and the second number is decreased by 6, then the ratio becomes 4 : 6. What is the sum of the original two numbers?
650
681
665
663
663
Use the cross-multiplication method: Multiply (56 - 48) = |30 - 32| = 2 units. The impact of the shifts is (136) and (-64) = 78 and -24. Net difference is 78 - (-24) = 102. So 2 units = 102, 1 unit = 51. Total sum = (5+8)*units = 13 * 51 = 663.
Two numbers are in ratio 5:8. Adding 13 to the first and subtracting 6 from the second changes the ratio to 4:6.
8xтИТ65x+13тАЛ=64тАЛ
Use the cross-multiplication method: Multiply (56 - 48) = |30 - 32| = 2 units. The impact of the shifts is (136) and (-64) = 78 and -24. Net difference is 78 - (-24) = 102. So 2 units = 102, 1 unit = 51. Total sum = (5+8)*units = 13 * 51 = 663.
Students often cross-multiply incorrectly or mix up the additions and subtractions (treating -6 as +6), leading to a wrong value for x.
Define the variables
Let the original numbers be 5x and 8x based on the given ratio of 5:8.
5x,8x
Formulate the equation
According to the problem, adding 13 to the first and subtracting 6 from the second results in the ratio 4:6.
8xтИТ65x+13тАЛ=64тАЛ
Solve for x
Simplify the ratio 4/6 to 2/3 and cross-multiply: 3(5x+13)=2(8xтИТ6)тЗТ15x+39=16xтИТ12. Rearranging gives x=39+12=51.
x=51
Calculate the sum
The original numbers are 5x=5├Ч51=255 and 8x=8├Ч51=408. Their sum is 255+408=663.
5x+8x=13x=13├Ч51=663
D is correct because the calculated sum of the two numbers is 663.
This cross-multiplication technique is highly effective for 'mixture' problems and 'age-based' ratio questions in Quantitative Aptitude sections.