Identify the given sequence

The series of natural numbers from $1$ to $91$ forms an arithmetic progression (AP) with a common difference $d = 1$.

$n = 91, \quad a = 1, \quad l = 91$

Recall the average formula for AP

For any arithmetic progression, the average of the terms is given by the mean of the first and the last term: $\frac{\text{First Term} + \text{Last Term}}{2}$.

$\text{Average} = \frac{a + l}{2}$

Substitute the values

Substituting $a = 1$ and $l = 91$ into the formula: $\text{Average} = \frac{1 + 91}{2}$.

$\text{Average} = \frac{92}{2}$

Calculate the final value

Dividing $92$ by $2$ gives the final average value.

$\text{Average} = 46$