What is the total capacitance when two capacitors C1 and C2 are connected in series?

Question

Examoogle · Accepted Answer

$\frac{C_1C_2}{C_1+C_2}$

Explanation: Given: Two capacitors C1 and C2 are connected in a series configuration.

Formula Used: $$\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2}$$

Steps: State the Series Law: For capacitors connected in series, the reciprocal of the equivalent capacitance is the sum of the reciprocals of the individual capacitances.. Find Common Denominator: To combine the fractions on the right side, find the common denominator, which is $C_1C_2$.. Solve for Equivalent Capacitance: Take the reciprocal of both sides to isolate $C_{eq}$.

Answer: C is correct because the series combination of two capacitors results in an equivalent capacitance given by the product of the capacitances divided by their sum.

Exam Tip: This concept is the mathematical dual of resistors in parallel; capacitors in series behave like resistors in parallel, and capacitors in parallel behave like resistors in series.

Related Questions

Discussion (0)