Join 60,000+ competitive exam aspirants
Working together, A and B can finish a task in 12 days. If A alone can finish it in 20 days, how long will B take to finish it alone?
30 days
35 days
40 days
25 days
30 days
Use the formula yтИТxx├ЧyтАЛ, where x is the time taken by A alone and y is the time taken by both together. Here, x=20 and y=12.
Time taken by A and B together (A+B) = 12 days. Time taken by A alone = 20 days.
B=AтИТ(A+B)A├Ч(A+B)тАЛ
Use the formula yтИТxx├ЧyтАЛ, where x is the time taken by A alone and y is the time taken by both together. Here, x=20 and y=12.
Students often add the days instead of finding the difference, incorrectly calculating 20+12=32 or getting confused with the reciprocal rule B1тАЛ=121тАЛтИТ201тАЛ and failing to invert the result at the final step.
Define given rates
The work rate of A and B combined is 1/12 of the work per day, and A's individual work rate is 1/20 of the work per day.
B1тАЛ=121тАЛтИТ201тАЛ
Calculate the difference of fractions
Find a common denominator, which is 60. Then calculate 605тАЛтИТ603тАЛ=602тАЛ
602тАЛ=301тАЛ
Final inversion
Since 1/B=1/30, B takes 30 days to complete the work alone.
B=30
A is correct because the calculation 121тАЛтИТ201тАЛ=301тАЛ results in 30 days for B to finish the task alone.
This inverse relationship between work and time is identical to the concept of Pipe and Cistern problems, where the inflow and outflow rates determine the net filling time.