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A, B, C, D, E, F, and G are sitting around a circular table, facing the centre (not necessarily in the same order). Only 2 people sit between C and F when counted from the right of C. A and D are immediate neighbours of G. E sits to the immediate left of B. Only 1 person sits between E and D when counted from the right of D. Who is sitting to the immediate right of G?
C
D
A
B
D
Fix the anchor (G) and its neighbors (A and D), then place others relative to them to quickly finalize the circular sequence.
Fix the anchor (G) and its neighbors (A and D), then place others relative to them to quickly finalize the circular sequence.
Establish the Anchor
Let G be at position 1. Since A and D are immediate neighbors of G, they occupy positions 7 and 2 in some order.
Apply Constraints for E, B, and D
E sits to the immediate left of B (B, E). Only 1 person is between E and D (counted from the right of D). Placing D at position 2 and G at 1, the right of D is position 3 (skip) and 4. So E is at 4, B is at 3. Now E(4) and D(2) have 1 person (position 3) between them. This fits.
Finalize Positions
Current sequence: G(1), D(2), B(3), E(4). Remaining are C, F, A. C and F have 2 people between them from the right of C. If C is at 6 and F is at 3 (occupied), we adjust: If G is 1, A is 7, D is 2. Then B is 3, E is 4. Remaining seats 5, 6. If C is 5, right of C is 6, 7 (2 people) then F is 1 (occupied). Placing C at 7 is impossible. Placing C at 6, right is 7, 1 (2 people) so F is 2 (occupied). By trial, the sequence is G(1), D(2), B(3), E(4), C(5), A(6), F(7). Counting right of C(5): 6, 7 (2 people). This fits. Therefore, D is to the immediate right of G.
A: C is not at the right of G; C: A is on the left of G; D: B is two places away from G.
B is correct because following the clockwise arrangement (G, D, B, E, C, A, F) places D immediately to the right of G.
In circular puzzles with 'counted from the right', always draw the circle and number the seats 1 to 7 clockwise to avoid directional errors.
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