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A constant force of 21 N moves a body through 3 m in its own direction. Work done is _____.
24 J
63 J
18 J
7 J
63 J
Work done is defined as the product of the magnitude of the force applied and the displacement of the object in the direction of the force. By multiplying the force of 21┬аN by the displacement of 3┬аm, we obtain 63┬аJ.
Work done is defined as the product of the magnitude of the force applied and the displacement of the object in the direction of the force. By multiplying the force of 21┬аN by the displacement of 3┬аm, we obtain 63┬аJ.
Think of pushing a shopping cart; the harder you push (force) and the further you walk (displacement), the more work you do.
WFS (Work = Force ├Ч Space/Displacement)
W=FтЛЕsтЛЕcos(╬╕) тАФ General formula for work done
W=F├Чs тАФ Simplified formula for force acting in the direction of displacement
According to the principle of mechanical work, when a constant force F acts on a body causing a displacement s in the same direction, the work done W is calculated using the dot product of the force and displacement vectors. Since the angle ╬╕ between force and displacement is 0┬░, the term cos(0┬░)=1 makes the formula simply W=F├Чs.
Work is a scalar quantity, having only magnitude and no direction.
The SI unit of work is the Joule (J), where 1┬аJ=1┬аNтЛЕm.
If the force is perpendicular to displacement, the work done is zero because cos(90┬░)=0.
Provides a simple quantification of energy transfer.
Does not account for the time taken, which would be power.
Calculating energy consumption in mechanical systems.
Analyzing physics problems involving motion and forces.
The constant force F=21┬аN and displacement s=3┬аm are given.
Option A is incorrect as it is a miscalculation. Option C is incorrect (21тИТ3=18). Option D is incorrect (21/3=7).
B is correct тАФ The work done is calculated as W=21┬аN├Ч3┬аm=63┬аJ.
Always check the direction of force relative to displacement; if they are not parallel, you must multiply by cos(╬╕).
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