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An object with a mass of 15 kg is placed 8 m above the ground. How much potential energy does the object have? (Using g = 9.8 m/s 2 )
1500 J
784 J
1176 J
980 J
1176 J
The gravitational potential energy of an object is the energy stored due to its position relative to the ground. Using the formula for potential energy, the calculation yields 1176 J.
The gravitational potential energy of an object is the energy stored due to its position relative to the ground. Using the formula for potential energy, the calculation yields 1176 J.
Think of a heavy stone held at a height; it has the 'potential' to do work (like breaking a surface) because gravity is pulling it down. The higher you lift it, or the heavier it is, the more 'potential' damage it can cause upon release.
PE=mтЛЕgтЛЕh тАФ Gravitational potential energy formula where m is mass, g is gravity, and h is height.
Gravitational potential energy (PE) is defined as the work done by a gravitational force to move an object to a certain height. It is determined by the mass of the object, the acceleration due to gravity, and the vertical height of the object. The energy is directly proportional to all three factors: PE=mgh.
Gravitational potential energy depends on mass, gravity, and height.
The SI unit for energy is Joules (J).
Energy is a scalar quantity.
Allows for the calculation of stored energy in mechanical systems.
Calculations assume a constant acceleration due to gravity (g).
Hydropower plants calculating energy from water held in a dam.
Engineering systems like cranes and elevators.
Standard acceleration due to gravity on Earth is approximately 9.8┬аm/s2.
Calculation: PE=15┬аkg├Ч9.8┬аm/s2├Ч8┬аm=1176┬аJ.
Option A is incorrect as it assumes g=10┬аm/s2 and 15├Ч10├Ч8=1200. Option B is incorrect as it is 80├Ч9.8. Option D is incorrect as it is 100├Ч9.8.
C is correct тАФ The potential energy is calculated using the product of mass, gravity, and height (15├Ч9.8├Ч8=1176┬аJ).
In competitive exams, always check if the question specifies the value of g (e.g., 9.8┬аm/s2 vs 10┬аm/s2) before performing the calculation to avoid precision errors.
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