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A cylindrical rod has an outer curved surface area of 7900┬аcm2. If the length of the rod is 3┬аcm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: (Take┬а╧А=722тАЛ)
419.12
417.52
418.94
420.85
418.94
Rearrange the formula to r=2╧АhCSAтАЛ and use r=2├Ч22├Ч37900├Ч7тАЛ to simplify calculations by dividing by common factors like 2.
Outer curved surface area of the cylinder (CSA) = 7900 cm┬▓, length (height h) = 3 cm, value of ╧А = 22/7.
CSA=2╧Аrh
Rearrange the formula to r=2╧АhCSAтАЛ and use r=2├Ч22├Ч37900├Ч7тАЛ to simplify calculations by dividing by common factors like 2.
Many students mistake the 'length' of the cylindrical rod for the diameter instead of the height h, or misapply the curved surface area formula by including the base areas.
Identify given values and formula
The formula for the curved surface area of a cylinder is CSA=2╧Аrh. Given CSA=7900, h=3, and ╧А=722тАЛ, we need to find the radius r.
r=2╧АhCSAтАЛ
Substitute the values
Plugging the values into the equation: r=2├Ч722тАЛ├Ч37900тАЛ
r=44├Ч37900├Ч7тАЛ
Solve for r
Calculating the numerator: 7900├Ч7=55300. Calculating the denominator: 44├Ч3=132. Then, r=13255300тАЛ.
rтЙИ418.93939...
Round to two decimal places
Rounding 418.93939 to two decimal places gives 418.94.
rтЙИ418.94
C is correct because the calculated radius r=13255300тАЛтЙИ418.94 cm.
This concept is a foundational part of Mensuration in geometry. Similar logic applies to finding missing dimensions in cones and spheres using their respective surface area or volume formulas.