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The difference between two parallel sides of a trapezium is 9 cm. The perpendicular distance between them is 52 cm. If the area of the trapezium is 988 cm 2 , find the lengths of the parallel sides (in cm).
29.5, 20.5
23.5, 14.5
35.5, 20.5
18.5, 12.5
23.5, 14.5
Check the options by taking their difference. Only 23.5 - 14.5 = 9. Since the average of the two sides multiplied by 52 must equal 988, check (a+b)/2 = 988/52 = 19. Only Option B gives (23.5 + 14.5)/2 = 38/2 = 19.
Area of trapezium A = 988 cm┬▓, height h = 52 cm, and difference between parallel sides (a - b) = 9 cm.
Area=21тАЛ├Ч(a+b)├Чh
Check the options by taking their difference. Only 23.5 - 14.5 = 9. Since the average of the two sides multiplied by 52 must equal 988, check (a+b)/2 = 988/52 = 19. Only Option B gives (23.5 + 14.5)/2 = 38/2 = 19.
Students often confuse the difference between sides (a - b) with the sum of sides (a + b) needed for the area formula.
Set up the area equation
Using the area formula for a trapezium, substitute the given height h=52 and Area A=988.
988=21тАЛ├Ч(a+b)├Ч52
Calculate the sum of parallel sides
Simplify the equation to find (a+b). Dividing 988 by 26 gives the sum.
a+b=52988├Ч2тАЛ=38
Solve the system of linear equations
We have two equations: a+b=38 and aтИТb=9. Adding them gives 2a=47, so a=23.5.
a=247тАЛ=23.5
Find the second side
Substitute a=23.5 into a+b=38 to find b.
b=38тИТ23.5=14.5
B is correct because the parallel sides calculate to 23.5 cm and 14.5 cm, satisfying both the area and the difference constraints.
This type of algebraic substitution is frequently used in geometry problems involving rectangle dimensions or perimeter-based area calculations.