Imagine melting a large block of ice of volume 216 cubic centimeters and pouring the water into smaller ice cube trays each holding 8 cubic centimeters; you will be able to fill exactly 27 small trays.

Large Volume divided by Small Volume gives the count!

According to the principle of conservation of mass and volume in melting and casting processes, the volume of the original metal equals the sum of the volumes of all the recast items. The volume of a cube is given by $V = a^3$, where $a$ is the side length. Thus, the ratio of volumes gives $n = \frac{V_{\text{large}}}{V_{\text{small}}} = \frac{6^3}{2^3} = \frac{216}{8} = 27$.

Always verify whether the problem asks for linear dimensions, surface areas, or volumes, as scaling factors differ ($a$ for linear, $a^2$ for area, and $a^3$ for volume).