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MathematicsMensuration
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A solid metallic cube of side 6 cm is melted and recast into smaller cubes of side 2 cm. How many smaller cubes can be formed?

A

9

B

18

C

27

D

36

Correct Answer

ЁЯУР MA тАв Math Concept & PrincipleMathematicsMensuration
Option C

27

Quick Summary:

When a solid metallic object is melted and recast into another shape, its total volume remains conserved. The number of smaller cubes formed is determined by dividing the volume of the original large cube by the volume of one smaller cube.

ЁЯФмSCScience SolutionConcept & Principle
ЁЯТб Explanation

When a solid metallic object is melted and recast into another shape, its total volume remains conserved. The number of smaller cubes formed is determined by dividing the volume of the original large cube by the volume of one smaller cube.

ЁЯТб Everyday Analogy (Real-World Intuition)

Imagine melting a large block of ice to fill small identical ice cube trays; the total amount of water (volume) remains constant throughout the process.

ЁЯФв Key Formulas

V=a3V = a^3V=a3 тАФ Volume of a cube with side length aaa

N=a13a23N = \frac{a_1^3}{a_2^3}N=a23тАЛa13тАЛтАЛ тАФ Number of recasted smaller items

тЪЩя╕П Working Principle

The principle of conservation of volume dictates that the total quantity of matter does not change during melting and recasting. Since the volume of a cube is given by V=a3V = a^3V=a3 (where aaa is the side length), the number of smaller cubes NNN is calculated as the ratio of their volumes: N=a13a23N = \frac{a_1^3}{a_2^3}N=a23тАЛa13тАЛтАЛ.

ЁЯУМ Key Points
  • тЦ╕

    Volume is conserved during physical recasting processes.

  • тЦ╕

    Linear scale factor must be cubed to find the volumetric ratio.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Metal casting and foundry operations

  • тЦ╕

    Recycling and reshaping metallic components

ЁЯУД Additional Information
  • тЦ╕

    Volume of large cube = 63=216extcm36^3 = 216 ext{ cm}^363=216extcm3.

  • тЦ╕

    Volume of small cube = 23=8extcm32^3 = 8 ext{ cm}^323=8extcm3. Number of cubes = 216/8=27216 / 8 = 27216/8=27.

ЁЯУК Diagram / Illustration
Volume Conservation in Recasting1Given DataLarge cube side = 6тАпcm, Small cube side = 2тАпcm2FormulaNumber of small cubes N = (Side_large)┬│ / (Side_small)┬│3CalculationN = 6┬│ / 2┬│ = 216 / 8 = 274Result27 smaller cubes27
тЬЕ

C is correct тАФ Exactly 27 smaller cubes can be formed by taking the ratio of the volume of the large cube to the small cube.

Core Concepts Used
Click any tag to open in AI Tutor
Conservation of Volume Mensuration Cubic Scaling
ЁЯТб EXAM TIP

Always remember that scaling dimensions by a factor kkk changes the volume by a factor of k3k^3k3, not kkk.

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