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ElectricalBasic Electrical
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Average value of current is given by

A

ImI_mImтАЛ

B

0.5Im0.5I_m0.5ImтАЛ

C

0.707Im0.707I_m0.707ImтАЛ

D

0.637Im0.637I_m0.637ImтАЛ

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalBasic Electrical
Option D

0.637Im0.637I_m0.637ImтАЛ

Quick Summary:

The average value of a sinusoidal alternating current over a half-cycle is defined as the arithmetic mean of all instantaneous values. For a symmetrical sinusoidal waveform, this is calculated as 2Im╧А\frac{2I_m}{\pi}╧А2ImтАЛтАЛ, which evaluates to approximately 0.637Im0.637I_m0.637ImтАЛ.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The average value of a sinusoidal alternating current over a half-cycle is defined as the arithmetic mean of all instantaneous values. For a symmetrical sinusoidal waveform, this is calculated as 2Im╧А\frac{2I_m}{\pi}╧А2ImтАЛтАЛ, which evaluates to approximately 0.637Im0.637I_m0.637ImтАЛ.

ЁЯФв Key Formulas

Iavg=2Im╧АI_{avg} = \frac{2I_m}{\pi}IavgтАЛ=╧А2ImтАЛтАЛ тАФ Average value for a half-cycle

Irms=Im2тЙИ0.707ImI_{rms} = \frac{I_m}{\sqrt{2}} \approx 0.707I_mIrmsтАЛ=2тАЛImтАЛтАЛтЙИ0.707ImтАЛ тАФ Root Mean Square value

тЪЩя╕П Working Principle

The average value is derived by integrating the instantaneous current i=ImsinтБб(╧Йt)i = I_m \sin(\omega t)i=ImтАЛsin(╧Йt) over the interval from 000 to ╧А\pi╧А and dividing by the interval duration ╧А\pi╧А. Mathematically, Iavg=1╧АтИл0╧АImsinтБб(╬╕)d╬╕=Im╧А[тИТcosтБб(╬╕)]0╧А=2Im╧АтЙИ0.637ImI_{avg} = \frac{1}{\pi} \int_{0}^{\pi} I_m \sin(\theta) d\theta = \frac{I_m}{\pi} [-\cos(\theta)]_0^{\pi} = \frac{2I_m}{\pi} \approx 0.637I_mIavgтАЛ=╧А1тАЛтИл0╧АтАЛImтАЛsin(╬╕)d╬╕=╧АImтАЛтАЛ[тИТcos(╬╕)]0╧АтАЛ=╧А2ImтАЛтАЛтЙИ0.637ImтАЛ. Over a full cycle, the average value of a pure sinusoidal wave is zero due to the cancellation of the positive and negative half-cycles.

ЁЯУМ Key Points
  • тЦ╕

    The average value is strictly defined for a half-cycle in AC circuits.

  • тЦ╕

    Form factor is defined as the ratio of RMS value to Average value, which is тЙИ1.11\approx 1.11тЙИ1.11 for a sine wave.

  • тЦ╕

    The average value over a complete period for a symmetrical AC signal is zero.

тЬЕ Advantages
  • тЦ╕

    Useful in calculating DC equivalent output in half-wave and full-wave rectifiers.

  • тЦ╕

    Simplifies analysis of pulsating DC components in electrical machines.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Not representative of the actual power-delivering capability of the AC signal.

  • тЦ╕

    Mathematically zero over a full cycle, requiring half-cycle rectification for meaningful measurement.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Moving coil (PMMC) instrument calibration.

  • тЦ╕

    Design and analysis of rectifier circuits.

ЁЯУД Additional Information
  • тЦ╕

    Option B (0.5Im) is incorrect and holds no standard physical significance for sine waves.

  • тЦ╕

    Option C (0.707Im) refers to the RMS (Root Mean Square) value, not the average value.

ЁЯУК Diagram / Illustration
Average Current Calculation
2Im2I_m2ImтАЛ
╧А\pi╧А
Result: тЙИ0.637Im\approx 0.637 I_mтЙИ0.637ImтАЛ
тЬЕ

D is correct тАФ The average value of a sinusoidal current over one half-cycle is mathematically derived as 2Im/╧А2I_m/\pi2ImтАЛ/╧А, resulting in 0.637Im0.637I_m0.637ImтАЛ.

Core Concepts Used
Click any tag to open in AI Tutor
AC Fundamentals Sinusoidal Waveform Average vs RMS Values
ЁЯТб EXAM TIP

Always distinguish between Average and RMS values; recall that Form Factor = RMS/Average = 1.11 for sinusoidal signals.

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