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Ay, Bk, Cv, Du, Es, Fo and Gw are sitting around a circular table facing the centre. Cv sits to the immediate right of Ay. Du sits third to the left of Ay. Bk is the immediate neighbour of Fo and Cv. Gw is not an immediate neighbour of Du. What is the position of Es with respect to Fo?
Third to the left
Immediate left
Immediate right
Second to the right
Second to the right
Fix the reference point (Ay) at the 6 o'clock position and place others relative to the center to quickly deduce the cycle.
Fix the reference point (Ay) at the 6 o'clock position and place others relative to the center to quickly deduce the cycle.
Initial Positioning
Place Ay at position 1. Cv is to the immediate right, so Cv is at position 2 (clockwise). Du is third to the left of Ay, placing Du at position 5 (counter-clockwise 1-8-7-6-5 sequence).
Applying Neighbor Constraints
Bk is a neighbor of Cv and Fo. Since Cv is at 2, Bk must be at 3. Since Bk is a neighbor of Fo, Fo must be at 4. Now we have: Ay(1), Cv(2), Bk(3), Fo(4), Du(5).
Final Filling and Verification
Remaining spots are 6 and 7. Gw cannot be a neighbor of Du(5), so Gw must be at 7. This leaves Es at position 6. The sequence is: 1:Ay, 2:Cv, 3:Bk, 4:Fo, 5:Du, 6:Es, 7:Gw.
Calculating Relative Position
Fo is at 4. Counting right from Fo (counter-clockwise): 3 is first right, 2 is second right, 1 is third right. Counting left from Fo (clockwise): 5 is first left, 6 is second left. Wait, the seating is circular facing center. Position 4 (Fo). Right of 4 is 3, 2, 1. Left of 4 is 5, 6, 7. Es(6) is second to the right of Fo(4).
A: Third to left is Gw, B: Immediate left is Du, C: Immediate right is Bk. D is correct as Es is located two positions right from Fo.
D is correct because based on the circular arrangement Ay-Cv-Bk-Fo-Du-Es-Gw, Es is positioned second to the right of Fo.
In circular arrangements, always draw a rough circle with numbers 1-7. Never try to visualize mentally; sketching prevents index errors.
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