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ElectricalPower System
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Constant power locus of a transmission line at a particular sending end and receiving end voltage is

A

Straight line

B

Circle

C

Parabola

D

Ellipse

Correct Answer

⚙️ TE • Technical Concept & PrincipleElectricalPower System
Option B

Circle

Quick Summary:

The constant power locus represents all possible combinations of active (P) and reactive (Q) power that a transmission line can deliver for fixed sending-end (VSV_SVS​) and receiving-end (VRV_RVR​) voltages. This locus manifests as a circle in the complex power plane, centered at a point determined by the transmission line parameters (A,BA, BA,B constants).

⚙️TETechnical SolutionConcept & Principle
💡 Explanation

The constant power locus represents all possible combinations of active (P) and reactive (Q) power that a transmission line can deliver for fixed sending-end (VSV_SVS​) and receiving-end (VRV_RVR​) voltages. This locus manifests as a circle in the complex power plane, centered at a point determined by the transmission line parameters (A,BA, BA,B constants).

🔢 Key Formulas

PR+jQR=∣VS∣∣VR∣∣B∣∠(β−δ)−∣A∣∣VR∣2∣B∣∠(β−α)P_R + jQ_R = \frac{|V_S||V_R|}{|B|} \angle (\beta - \delta) - \frac{|A||V_R|^2}{|B|} \angle (\beta - \alpha)PR​+jQR​=∣B∣∣VS​∣∣VR​∣​∠(β−δ)−∣B∣∣A∣∣VR​∣2​∠(β−α)

(PR−P0)2+(QR−Q0)2=(∣VS∣∣VR∣∣B∣)2(P_R - P_0)^2 + (Q_R - Q_0)^2 = \left( \frac{|V_S||V_R|}{|B|} \right)^2(PR​−P0​)2+(QR​−Q0​)2=(∣B∣∣VS​∣∣VR​∣​)2

⚙️ Working Principle

The relationship between VSV_SVS​ and VRV_RVR​ is given by the transmission equation VS=AVR+BIRV_S = AV_R + BI_RVS​=AVR​+BIR​. The receiving end complex power SR=PR+jQR=VRIR∗S_R = P_R + jQ_R = V_R I_R^*SR​=PR​+jQR​=VR​IR∗​. Substituting IRI_RIR​ into the transmission equation yields a quadratic form in PRP_RPR​ and QRQ_RQR​ with equal coefficients for PR2P_R^2PR2​ and QR2Q_R^2QR2​, which mathematically defines the equation of a circle.

📌 Key Points
  • ▸

    The radius of the constant power circle is determined by ∣VS∣∣VR∣∣B∣\frac{|V_S||V_R|}{|B|}∣B∣∣VS​∣∣VR​∣​.

  • ▸

    The circle center depends on the line constants A=∣A∣∠αA = |A|\angle \alphaA=∣A∣∠α and B=∣B∣∠βB = |B|\angle \betaB=∣B∣∠β.

  • ▸

    These loci are vital for determining power flow limits and stability regions in power systems.

  • ▸

    A change in VSV_SVS​ or VRV_RVR​ shifts the center or changes the radius, resulting in a family of concentric or overlapping circles.

✅ Advantages
  • ▸

    Provides a clear graphical representation of power delivery limits.

  • ▸

    Essential for calculating the stability margin of transmission lines.

❌ Disadvantages / Limitations
  • ▸

    Complex calculation for long lines requiring distributed parameter modeling.

  • ▸

    Assumes constant voltage magnitudes which may not hold during disturbances.

🛠️ Applications / Uses
  • ▸

    Power system stability analysis.

  • ▸

    Design of reactive power compensation devices (SVC/STATCOM).

  • ▸

    Load flow analysis at the planning stage.

📄 Additional Information
  • ▸

    The locus is specifically a circle in the P-Q plane.

  • ▸

    Option A (Straight line) represents the locus of power at constant current, not constant voltage.

  • ▸

    The circle is often referred to as the 'Receiving End Power Circle Diagram'.

📊 Diagram / Illustration
PQCircle
Center:(−∣A∣∣VR∣2∣B∣cos⁡(β−α),−∣A∣∣VR∣2∣B∣sin⁡(β−α))Center: (-(|A||V_R|^2 / |B|)\cos(\beta-\alpha), -(|A||V_R|^2 / |B|)\sin(\beta-\alpha))Center:(−∣B∣∣A∣∣VR​∣2​cos(β−α),−∣B∣∣A∣∣VR​∣2​sin(β−α))
✅

B is correct — The constant power locus of a transmission line for fixed terminal voltages is a circle in the complex P-Q plane.

Core Concepts Used
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Transmission line ABCD parameters Complex power flow Power circle diagram
💡 EXAM TIP

Always remember that in the complex power plane (P vs Q), any equation of the form (P−P0)2+(Q−Q0)2=R2(P-P_0)^2 + (Q-Q_0)^2 = R^2(P−P0​)2+(Q−Q0​)2=R2 signifies a circle, which frequently appears in power system stability questions.

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