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Each of P, Q, R, S, T, U and V has an exam on a different day of the same week, starting from Monday and ending on Sunday. R has an exam on one of the days after Thursday but not on Saturday. Only two people have an exam between R and Q. V has an exam immediately before Q. As many people have an exam before V as after U. P has an exam immediately before T. More than two people have an exam between T and S. Who has an exam on Tuesday?
Q
P
T
V Question ID : 441009786795 Option 1 ID : 4410093101180 Option 2 ID : 4410093101179 Option 3 ID : 4410093101182 Option 4 ID : 4410093101181 Status : Answered Chosen Option : C
T
Start by fixing R, which has only two valid positions (Friday, Sunday), then place Q and V to immediately restrict the remaining slots.
Start by fixing R, which has only two valid positions (Friday, Sunday), then place Q and V to immediately restrict the remaining slots.
Establish R, Q and V positions
R is after Thursday but not Saturday, so R is Friday or Sunday. If R is Sunday, Q must be Thursday (two gaps). V is immediately before Q, so V is Wednesday. Before V is 2 people (Mon, Tue), so after U must be 2 people (Sat, Sun). But R is Sunday, contradiction. Thus, R must be Friday. Two gaps between R and Q means Q is Monday. V is immediately before Q is impossible (Q is Monday). Wait, if Q is Monday, V cannot be before Q. Let us re-evaluate: If R is Friday, Q is Monday is wrong. Let's try Q on Tuesday: R (Fri) - Q (Tue) is 2 gaps (Wed, Thu). V is immediately before Q, so V is Monday. Before V is 0 people, so after U is 0 people. Thus, U is Sunday. Remaining: P, T, S.
Place P, T and S
Days filled: Mon=V, Tue=Q, Fri=R, Sun=U. P is immediately before T (PT block). P and T must be Wed and Thu. S must be Saturday. Check condition: More than two people between T (Thu) and S (Sat). T is Thu, S is Sat. Only 1 person (Fri) between them. This fails. Let's re-try: If R is Friday, and Q is Monday, there is no place for V. If R is Friday and Q is Thursday, then V is Wednesday. Before V (Wed) is 2 people (Mon, Tue), so after U is 2 people (Sat, Sun). U must be Friday? No, R is Friday. Let's re-check: If Q is Sunday, R is Thursday. Not allowed. If Q is Wednesday, R is Sunday (Sat, Fri, Thu). V is Tuesday. Before V (Tue) is 1 person (Mon), so after U is 1 person (Sat). U is Saturday. P and T must be together: P(Thu), T(Fri). Remaining S is Monday. T(Fri) to S(Mon) has 2 people (Sat, Sun). Condition 'more than two' fails. Final try: Q is Thursday, V is Wednesday, R is Sunday. Mon=S, Tue=P, Wed=V, Thu=Q, Fri=T, Sat=U, Sun=R. Check: P(Tue), T(Fri). Between T and S: Mon, Tue, Wed, Thu = 4 people. This works.
A: Q is on Thursday, not Tuesday. B: P is on Tuesday, but the question asks for the person, and P is correct. Wait, the official key says T, let's re-verify: P(Tue), T(Wed), V(Thu), Q(Fri), R(Sun), S(Mon), U(Sat). Between T and S: 1 person. Let's re-verify T: If T is Tuesday, P is Monday. V is Wednesday, Q is Thursday, R is Sunday. S is Saturday. U is Friday. Between T(Tue) and S(Sat) are Wed, Thu, Fri (3 people). This fits 'more than two'. Therefore T is Tuesday.
C is correct because placing T on Tuesday allows P to be on Monday and satisfies the condition of having more than two people between T and S.
In scheduling puzzles, always prioritize the most restricted variable (like R) to anchor the rest of the timeline.
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