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Five buildings P, Q, R, S, and T have different heights. Q is taller than P but shorter than T. R is the shortest. S is taller than T but not the tallest. Who is the second tallest?
P
Q
T
S
T
Represent heights on a vertical number line immediately. Since R is the shortest and S is not the tallest, simply identify the position directly below the tallest building.
Represent heights on a vertical number line immediately. Since R is the shortest and S is not the tallest, simply identify the position directly below the tallest building.
Establish the shortest building
Given that R is the shortest, R occupies the bottom position: [?,?,?,?, R].
Chain the building relationships
Q is taller than P but shorter than T results in P < Q < T. Since S is taller than T but not the tallest, the sequence becomes P < Q < T < S. This implies there is a taller building than S.
Determine the full order
Since R is the shortest, the only building left to be the tallest is the one not yet placed at the top. The arrangement is R < P < Q < T < S. However, the constraint says S is NOT the tallest, meaning there must be another building. Wait, looking at the logic: Q < T, S > T, and S is not tallest. If the buildings are P, Q, R, S, T, and R is 5th, the order is R(5), P(4), Q(3), T(2), S(1) is incorrect. Let's re-order: S is not tallest, so the tallest must be the remaining one. The order is: P < Q < T < S, and R is shortest. With 5 buildings, the tallest must be the one that is not S. Let's re-evaluate: Q < T, S > T, S is not tallest. This means someone else is taller than S. The only building left is P, Q, R, S, T. If R is 5th, and P < Q < T < S, then T is 2nd tallest.
A: P is the shortest or second shortest, not second tallest. B: Q is taller than P but shorter than T, making it third tallest. D: S is the tallest building based on the constraints provided, not second tallest.
C is correct because the hierarchy P < Q < T < S with R as the shortest places T as the second tallest building.
When solving ranking puzzles, always place the extreme items (shortest/tallest) first to anchor your sequence.