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In pure capacitor circuit, voltage is calculated by
V=iR
V=iXL
V=iXC
V=iLC
V=iXC
Quick Summary: In a pure capacitor circuit under AC conditions, the voltage across the capacitor is calculated using the product of the current and the capacitive reactance. Capacitive reactance represents the opposition offered by the capacitor to the flow of alternating current.
In a pure capacitor circuit under AC conditions, the voltage across the capacitor is calculated using the product of the current and the capacitive reactance. Capacitive reactance represents the opposition offered by the capacitor to the flow of alternating current.
V=IXC — Voltage across a capacitor
XC=2πfC1 — Capacitive reactance formula
The opposition to current in a capacitor is defined as XC=2πfC1. Because the voltage in an AC circuit follows Ohm's law in phasor form, the magnitude of the voltage drop across the pure capacitive element is given by V=I×XC. This relation holds because XC acts as the frequency-dependent resistance for the capacitive circuit.
Capacitive reactance XC is inversely proportional to frequency f and capacitance C.
In a purely capacitive circuit, the current leads the voltage by exactly 90° (2π radians).
Units for XC are Ohms (Ω).
Provides energy storage in electric fields
Essential for power factor correction
High reactance at low frequencies
Potential for dielectric breakdown under overvoltage
Filtering circuits in power supplies
Coupling and decoupling in signal processing
Option A (V=iR) describes a pure resistive circuit.
Option B (V=iXL) describes a pure inductive circuit where XL=2πfL.
Option D (V=iLC) is dimensionally incorrect for voltage.
C is correct — The voltage drop across a pure capacitor is the product of the RMS current and its capacitive reactance (XC).
Always remember that in AC circuits, 'Resistance' generalizes to 'Impedance' (Z). For pure components, Z simplifies to R, jXL, or −jXC.