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In pure capacitor circuit, angle between voltage and current is
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90
Quick Summary: In a pure capacitor circuit, the current leads the voltage by an exact phase angle of $90^{\circ}$ (or $\frac{\pi}{2}$ radians). This occurs because the capacitor opposes any change in voltage by storing energy in an electric field, creating a phase shift between the sinusoidal signals.
In a pure capacitor circuit, the current leads the voltage by an exact phase angle of 90° (or 2π radians). This occurs because the capacitor opposes any change in voltage by storing energy in an electric field, creating a phase shift between the sinusoidal signals.
i=Cdtdv — Instantaneous current-voltage relationship
XC=2πfC1 — Capacitive reactance
The current in a capacitor is defined as i(t)=Cdtdv. If voltage is v(t)=Vmsin(ωt), then i(t)=Cdtd(Vmsin(ωt))=ωCVmcos(ωt)=ωCVmsin(ωt+90°). The derivative of the sine function results in a cosine, which is inherently shifted by 90° leading.
A pure capacitor is a non-dissipative element; it stores and releases energy.
The power factor for a pure capacitive circuit is zero (leading).
Average power consumed by a pure capacitor over a cycle is zero.
Zero active power consumption in ideal conditions
Used for power factor correction in industrial systems
Ideal pure capacitors do not exist; all have some Equivalent Series Resistance (ESR)
Can cause resonance issues in power grids
Filtering circuits
Coupling and decoupling applications
Power factor improvement banks
The phase angle is defined as ϕ=90° for a pure capacitor.
Option A (0°) represents a purely resistive circuit.
Options B (30°) and C (60°) represent R-C series circuits where the phase angle depends on the values of R and C.
D is correct — In a pure capacitor, the current leads the voltage by 90°.
Remember 'ELI the ICE man': In an Inductor (L), E leads I; in a Capacitor (C), I leads E.