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ElectricalBasic Electrical
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In pure capacitor circuit, angle between voltage and current is

A

0

B

30

C

60

D

90

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalBasic Electrical
Option D

90

Quick Summary:

In a pure capacitor circuit, the current leads the voltage by an exact phase angle of 90┬░90┬░90┬░ (or ╧А2\frac{\pi}{2}2╧АтАЛ radians). This occurs because the capacitor opposes any change in voltage by storing energy in an electric field, creating a phase shift between the sinusoidal signals.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

In a pure capacitor circuit, the current leads the voltage by an exact phase angle of 90┬░90┬░90┬░ (or ╧А2\frac{\pi}{2}2╧АтАЛ radians). This occurs because the capacitor opposes any change in voltage by storing energy in an electric field, creating a phase shift between the sinusoidal signals.

ЁЯФв Key Formulas

i=Cdvdti = C \frac{dv}{dt}i=CdtdvтАЛ тАФ Instantaneous current-voltage relationship

XC=12╧АfCX_C = \frac{1}{2\pi fC}XCтАЛ=2╧АfC1тАЛ тАФ Capacitive reactance

тЪЩя╕П Working Principle

The current in a capacitor is defined as i(t)=Cdvdti(t) = C \frac{dv}{dt}i(t)=CdtdvтАЛ. If voltage is v(t)=VmsinтБб(╧Йt)v(t) = V_m \sin(\omega t)v(t)=VmтАЛsin(╧Йt), then i(t)=Cddt(VmsinтБб(╧Йt))=╧ЙCVmcosтБб(╧Йt)=╧ЙCVmsinтБб(╧Йt+90┬░)i(t) = C \frac{d}{dt}(V_m \sin(\omega t)) = \omega C V_m \cos(\omega t) = \omega C V_m \sin(\omega t + 90┬░)i(t)=CdtdтАЛ(VmтАЛsin(╧Йt))=╧ЙCVmтАЛcos(╧Йt)=╧ЙCVmтАЛsin(╧Йt+90┬░). The derivative of the sine function results in a cosine, which is inherently shifted by 90┬░90┬░90┬░ leading.

ЁЯУМ Key Points
  • тЦ╕

    A pure capacitor is a non-dissipative element; it stores and releases energy.

  • тЦ╕

    The power factor for a pure capacitive circuit is zero (leading).

  • тЦ╕

    Average power consumed by a pure capacitor over a cycle is zero.

тЬЕ Advantages
  • тЦ╕

    Zero active power consumption in ideal conditions

  • тЦ╕

    Used for power factor correction in industrial systems

тЭМ Disadvantages / Limitations
  • тЦ╕

    Ideal pure capacitors do not exist; all have some Equivalent Series Resistance (ESR)

  • тЦ╕

    Can cause resonance issues in power grids

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Filtering circuits

  • тЦ╕

    Coupling and decoupling applications

  • тЦ╕

    Power factor improvement banks

ЁЯУД Additional Information
  • тЦ╕

    The phase angle is defined as ╧Х=90┬░\phi = 90┬░╧Х=90┬░ for a pure capacitor.

  • тЦ╕

    Option A (0┬░0┬░0┬░) represents a purely resistive circuit.

  • тЦ╕

    Options B (30┬░30┬░30┬░) and C (60┬░60┬░60┬░) represent R-C series circuits where the phase angle depends on the values of R and C.

ЁЯУК Diagram / Illustration
Phase Relationshipt
i(t)i(t)i(t)
v(t)v(t)v(t)
тЬЕ

D is correct тАФ In a pure capacitor, the current leads the voltage by 90┬░90┬░90┬░.

Core Concepts Used
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Phase shift in reactive elements Capacitive reactance AC circuit analysis
ЁЯТб EXAM TIP

Remember 'ELI the ICE man': In an Inductor (L), E leads I; in a Capacitor (C), I leads E.

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