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In pure inductor circuit, which quantity is lagging
Current
Voltage
Both of these
None of these
Current
Quick Summary: In a pure inductive circuit, the current lags the applied voltage by exactly 90 degrees or $\frac{\pi}{2}$ radians. This occurs because the inductor opposes any change in current, resulting in a phase shift where the voltage peak leads the current peak.
In a pure inductive circuit, the current lags the applied voltage by exactly 90 degrees or 2π radians. This occurs because the inductor opposes any change in current, resulting in a phase shift where the voltage peak leads the current peak.
XL=2πfL — Inductive Reactance in ohms
v(t)=Ldtdi — Voltage-Current relationship for an inductor
According to Faraday's Law of Electromagnetic Induction, the voltage across an inductor is given by v(t)=Ldtdi. When a sinusoidal voltage v=Vmsin(ωt) is applied, the current i(t) becomes ωLVmsin(ωt−90°). The back-EMF generated by the change in current causes the current to be delayed relative to the voltage.
The phase angle difference is exactly 90 degrees.
The power factor of a pure inductor is zero (lagging).
Inductors store energy in the form of a magnetic field.
Average power consumed by a pure inductor over one cycle is zero.
Provides high impedance to high-frequency signals
Essential for filter and oscillator circuit design
Cannot dissipate real power
Physical inductors always possess internal resistance causing losses
AC motor starting circuits
RF tuning and frequency filtering
Transformer windings
Option B is incorrect because voltage leads the current in an inductive circuit, whereas current leads voltage only in a capacitive circuit.
The term 'lagging' refers to the time-domain peak of the current occurring after the peak of the voltage.
A is correct — In a pure inductive circuit, the current waveform lags behind the applied voltage waveform by a phase angle of 90°.
Remember the mnemonic 'ELI the ICE man': In an Inductor (L), E leads I; in a Capacitor (C), I leads E.