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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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In pure resistor circuit, voltage is calculated by
V=iR
V=iXL
V=iXC
V=iLC
V=iR
Quick Summary: In a pure resistive circuit, the voltage drop across the resistor is governed by Ohm's Law. This law states that the potential difference across a conductor is directly proportional to the current flowing through it, given a constant resistance $R$.
In a pure resistive circuit, the voltage drop across the resistor is governed by Ohm's Law. This law states that the potential difference across a conductor is directly proportional to the current flowing through it, given a constant resistance R.
V=iR — Ohm's Law for resistive elements
P=i2R — Power dissipation in a resistor
In a pure resistor, the electrical energy is converted into thermal energy due to collisions between electrons and the lattice structure of the material. Since there is no phase shift between current and voltage in a resistor (phi=0°\°), the instantaneous voltage v(t) and current i(t) are always in phase, and their relationship is defined simply by v(t)=i(t)R.
Resistors are passive linear components where current and voltage remain in phase.
The resistance R is independent of frequency f.
Energy in a resistor is dissipated as heat, following Joule's Law.
Simple linear relationship.
No frequency dependence.
Energy is always dissipated as heat (loss).
Cannot store electrical energy.
Current limiting in circuits.
Voltage division and signal conditioning.
Option B (V=iXL) represents the voltage drop across a pure inductor.
Option C (V=iXC) represents the voltage drop across a pure capacitor.
Option D is dimensionally incorrect for any standard circuit element.
A is correct — The voltage across a pure resistor is given by the product of current and resistance, following Ohm's Law.
Remember that while V=iZ is the general formula for AC, for a pure resistor Z=R and the phase angle is zero, which simplifies the expression significantly.