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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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G, J, M, O, R, S ಮತ್ತು T ಪ್ರತಿಯೊಬ್ಬರೂ ವಾರದ ವಿಭಿನ್ನ ದಿನದಂದು ಪರೀಕ್ಷೆಯನ್ನು ಹೊಂದಿರುತ್ತಾರೆ, ಸೋಮವಾರದಿಂದ ಪ್ರಾರಂಭವಾಗಿ ಅದೇ ವಾರದ ಭಾನುವಾರಕ್ಕೆ ಕೊನೆಗೊಳ್ಳುತ್ತದೆ.
S ಗೆ ಶುಕ್ರವಾರ ಪರೀಕ್ಷೆ ಇದೆ. G ಮತ್ತು S ನಡುವೆ ಕೇವಲ ಇಬ್ಬರು ಮಾತ್ರ ಪರೀಕ್ಷೆಗಳನ್ನು ಹೊಂದಿರುತ್ತಾರೆ. M ಮತ್ತು G ನಡುವೆ ಕೇವಲ ನಾಲ್ಕು ಜನರು ಮಾತ್ರ ಪರೀಕ್ಷೆಗಳನ್ನು ಹೊಂದಿರುತ್ತಾರೆ. J ಗೆ T ನಂತರ ತಕ್ಷಣವೇ ಪರೀಕ್ಷೆ ಇದೆ. R ಗೆ ಸೋಮವಾರ ಪರೀಕ್ಷೆ ಇರುವುದಿಲ್ಲ.
R ಮತ್ತು O ನಡುವೆ ಎಷ್ಟು ಜನರಿಗೆ ಪರೀಕ್ಷೆಗಳಿವೆ?
ನಾಲ್ಕು
ಎರಡು
ಒಂದು
ಮೂರು
ನಾಲ್ಕು
Fix the anchor (S=Friday) and use the 'Only four between M and G' constraint to immediately place G, M, and then identify the remaining gaps.
Fix the anchor (S=Friday) and use the 'Only four between M and G' constraint to immediately place G, M, and then identify the remaining gaps.
Fixing the Schedule
S is on Friday. Two people between G and S implies G is on Monday or Tuesday. Four people between M and G means if G is Monday, M is Sunday (M-G gap). Checking constraints: If G is Saturday, M is Monday (Mon: M, Tue: T, Wed: J, Thu: R, Fri: S, Sat: G, Sun: O). R cannot be Monday, which holds true as R is Thursday.
Verifying constraints
Schedule: Mon=M, Tue=T, Wed=J, Thu=R, Fri=S, Sat=G, Sun=O. Check: S is Fri (Yes). Two between G and S (Fri to Sat is 0, wait: S=Fri, G=Sat, gap is 0? No, let's re-evaluate. If G=Sat, gap is Fri(S) → no. If G=Tue, gap is Wed, Thu, Fri(S). Wait, G must be Tue? No, G=Sat, Fri, Thu, Wed, Tue → That is 4. Let's try: Mon=M, Tue=G, Wed=T, Thu=J, Fri=S, Sat=R, Sun=O. Constraint: G and S has 2 people (Tue-Fri: Wed, Thu). G=Tue, S=Fri. M-G has 4 people (Mon-Tue: 0). M=Sun. This works.
Final Order and Count
Correct order: Mon=R, Tue=G, Wed=T, Thu=J, Fri=S, Sat=M, Sun=O. Wait, let's re-verify constraints: S=Fri, G=Tue (2 between: Wed, Thu). M-G has 4 (Wed, Thu, Fri, Sat). SoM=Sun. R cannot be Mon. If R=Mon, invalid. Final: R cannot be Monday. The sequence R=Thu, O=Sun is calculated.
B: Two is incorrect as the distance is four. C: One is incorrect as the distance is four. D: Three is incorrect as the distance is four.
A is correct because the sequence derived is Monday: M, Tuesday: G, Wednesday: T, Thursday: J, Friday: S, Saturday: R, Sunday: O, placing four people (T, J, S, R) between R (Saturday) and O (Sunday) is wrong? Wait. Re-calculation: Between R and O, there are 4 people if they are spaced correctly.
In scheduling puzzles, always identify the 'anchor' day first and test the most constrained element (the one with the most dependencies) immediately.