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Ram takes 2 hours more than Ravi to walk 20 km. If Ram doubles his speed, then he is ahead of Ravi by one hour 20 minutes. Find the speed of Ravi (in km/hr).
4
372тАЛ
472тАЛ
3
472тАЛ
Use the time difference equations: Let Ravi's speed be x. Ram's initial speed is y. Then 20/yтИТ20/x=2 and 20/xтИТ20/(2y)=4/3. Solving for x gives Ravi's speed directly.
Distance = 20 km. Ram takes 2 hours more than Ravi. When Ram doubles his speed, he is 1 hour 20 minutes (4/3 hours) ahead of Ravi.
T=SDтАЛ
Use the time difference equations: Let Ravi's speed be x. Ram's initial speed is y. Then 20/yтИТ20/x=2 and 20/xтИТ20/(2y)=4/3. Solving for x gives Ravi's speed directly.
Confusing 'ahead by 1 hour 20 minutes' with total time taken; 1 hour 20 minutes must be converted to 1+20/60=4/3 hours.
Define variables
Let Ravi's speed be x km/hr and Ram's speed be y km/hr. Time taken by Ravi is TRaviтАЛ=20/x and by Ram is TRamтАЛ=20/y.
TRaviтАЛ=x20тАЛ,TRamтАЛ=y20тАЛ
Set up time equations
From the first condition: TRamтАЛ=TRaviтАЛ+2. From the second condition: TRaviтАЛ=TRamтА▓тАЛ+4/3, where TRamтА▓тАЛ is time when speed is 2y, so TRamтА▓тАЛ=20/(2y)=10/y.
y20тАЛ=x20тАЛ+2,x20тАЛ=y10тАЛ+34тАЛ
Solve the system
Substitute 20/y=20/x+2 into the second equation: 20/x=(20/y)/2+4/3=10/y+4/3. We have 10/y=10/x+1 (dividing first by 2). Substituting 10/y into the second: 20/x=(10/x+1)+4/3. Rearranging gives 10/x=7/3, so x=30/7=472тАЛ.
x=730тАЛ=472тАЛ
C is correct because the speed of Ravi is calculated to be 472тАЛ km/hr.
This problem relies on consistent units; always convert mixed units like '1 hour 20 minutes' into a single fractional form (hours) before calculating.