Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
Find the mean of the following frequency distribution.
| x | 5 | 6 | 15 | 9 | 8 |
|---|---|---|---|---|---|
| f | 10 | 5 | 8 | 10 | 9 |
72113
82113
92113
62113
82113
Calculate ∑fixi and divide by the sum of frequencies (42). Since the denominator is 42, the fraction will have a denominator of 42 (or 21 after simplification). Check the integer part of the division to eliminate options quickly.
A frequency distribution table is provided with values of x (5, 6, 15, 9, 8) and their corresponding frequencies f (10, 5, 8, 10, 9).
x=∑fi∑(fi×xi)
Calculate ∑fixi and divide by the sum of frequencies (42). Since the denominator is 42, the fraction will have a denominator of 42 (or 21 after simplification). Check the integer part of the division to eliminate options quickly.
Students often miscalculate the summation of frequencies or the product sum ∑fixi by misaligning the values from the table.
Calculate the sum of frequencies
Add all frequencies provided in the table: 10+5+8+10+9=42.
∑fi=42
Calculate the sum of products
Multiply each xi by its corresponding fi and sum them: (5×10)+(6×5)+(15×8)+(9×10)+(8×9)=50+30+120+90+72=362.
∑fixi=362
Calculate the mean
Apply the mean formula: x=42362. Simplify the fraction by dividing by 2: 21181.
x=21181
Convert to mixed fraction
Perform division: 181÷21=8 with a remainder of 13. Thus, the mean is 82113.
82113
B is correct because the calculated mean of the frequency distribution is 82113.
This concept of weighted averages is foundational for statistics and data interpretation questions frequently appearing in competitive exams.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants