Join 60,000+ competitive exam aspirants
The average of the first 25 multiples of 3 is:
39
36
30
25
39
For the first n multiples of any number k, the average is always given by 2k├Ч(n+1)тАЛ. For k=3 and n=25, this is 23├Ч26тАЛ=39.
First 25 multiples of 3
Average=23├Ч(n+1)тАЛ
For the first n multiples of any number k, the average is always given by 2k├Ч(n+1)тАЛ. For k=3 and n=25, this is 23├Ч26тАЛ=39.
Students often try to calculate the sum of all 25 terms manually using the arithmetic progression sum formula, which consumes valuable time in the exam hall.
Identify the Series
The first 25 multiples of 3 form an arithmetic progression (AP) where the first term a=3, common difference d=3, and number of terms n=25.
3,6,9,тАж,3├Ч25=75
Apply AP Sum Formula
The sum of an AP is given by SnтАЛ=2nтАЛ(a+l), where l is the last term (75).
S25тАЛ=225тАЛ(3+75)=225├Ч78тАЛ=975
Calculate the Average
Average is calculated by dividing the total sum by the number of terms (25).
Average=25975тАЛ=39
Direct Formula Verification
Using the shortcut formula for the average of the first n multiples of k: 2k(n+1)тАЛ.
Average=23├Ч(25+1)тАЛ=23├Ч26тАЛ=39
A is correct because the average of the first 25 multiples of 3 is 39.
This shortcut applies to any arithmetic sequence where the average of an evenly spaced sequence is simply the average of the first and last terms: 23+75тАЛ=39.