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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
DK-HO
RY-VC
QX-UB
AD-GJ
AD-GJ
Find the difference in alphabetical position between the first and second letter, and the third and fourth letter of each letter-cluster pair.
Find the difference in alphabetical position between the first and second letter, and the third and fourth letter of each letter-cluster pair.
Analyze Option A (DK-HO)
D (4) + 7 = K (11); H (8) + 7 = O (15). Both pairs have a difference of +7.
Analyze Option B (RY-VC)
R (18) + 7 = Y (25); V (22) + 7 = C (3). Both pairs have a difference of +7.
Analyze Option C (QX-UB)
Q (17) + 7 = X (24); U (21) + 7 = B (2). Both pairs have a difference of +7.
Analyze Option D (AD-GJ)
A (1) + 3 = D (4); G (7) + 3 = J (10). Here the difference is +3, making it the odd one out.
A: DK-HO follows the +7 positional increment rule. B: RY-VC follows the +7 positional increment rule. C: QX-UB follows the +7 positional increment rule.
D is correct because the letter-cluster pairs AD-GJ follow a +3 alphabetical gap rule whereas the other three options follow a +7 rule.
When analyzing letter-cluster pairs in reasoning exams, always check the forward/backward positional difference between adjacent letters first before looking at vowels