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The income of X is 60% more than Y's income and the income of Y is 40% more than Z's income. By what percentage is X's income more than Z's income?
234%
134%
224%
124%
124%
Assume Z's income = 100. Then Y = 140, and X = 140 + 60% of 140 = 140 + 84 = 224. Hence X is 124% more than Z.
Income of X is 60% more than Y's income (X=1.6Y), and income of Y is 40% more than Z's income (Y=1.4Z).
Percentage More=ZX−Z×100
Assume Z's income = 100. Then Y = 140, and X = 140 + 60% of 140 = 140 + 84 = 224. Hence X is 124% more than Z.
Many students mistakenly add 60% and 40% directly to get 100%, forgetting that X's income is 60% more than Y, not Z directly.
Step 1: Assume Z's income
Let the income of Z be 100.
Z=100
Step 2: Find Y's income in terms of Z
Since the income of Y is 40% more than Z's income: Y=100+40% of 100=140
Y=140
Step 3: Find X's income in terms of Y
Since the income of X is 60% more than Y's income: X=140+60% of 140=140+10060×140=140+84=224
X=224
Step 4: Calculate percentage by which X's income is more than Z's income
Difference between X and Z is 224−100=124. Expressed as a percentage of Z: Percentage more=100224−100×100%=124%
124%
D is correct because X's income is calculated as 224 when Z's income is 100, which is 124% more than Z's income.
Successive percentage problems can also be solved using multipliers: X=1.6×1.4×Z=2.24Z, meaning X is 2.24 times Z, which corresponds to a 124% increase.