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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
AK-VF
XF-SC
SC-NX
RB-MW
XF-SC
Convert each letter to its alphabetical position. Check the difference or sum between pairs of letters in each letter-cluster pair.
Convert each letter to its alphabetical position. Check the difference or sum between pairs of letters in each letter-cluster pair.
Analyze Option A (AK - VF)
A is 1, K is 11 (difference of +10). V is 22, F is 6 (22 + 10 = 32, modulo 26 is 6, which is F). Both shifts are +10.
Analyze Option B (XF - SC)
X is 24, F is 6 (24 + 8 = 32, modulo 26 is 6, shift is +8). S is 19, C is 3 (19 + 10 = 29, modulo 26 is 3, shift is +10). The shifts do not match.
Analyze Option C (SC - NX)
S is 19, C is 3 (19 + 10 = 29, mod 26 is 3). N is 14, X is 24 (14 + 10 = 24). Both shifts are +10.
Analyze Option D (RB - MW)
R is 18, B is 2 (18 + 10 = 28, mod 26 is 2). M is 13, W is 23 (13 + 10 = 23). Both shifts are +10.
A: AK-VF follows a consistent +10 shift in alphabetical position. C: SC-NX follows a consistent +10 shift. D: RB-MW follows a consistent +10 shift.
B is correct because XF-SC has inconsistent forward shifts of +8 and +10, whereas the other three options all follow a uniform +10 alphabetical shift between the letter pairs.
When letter cluster pairs have large gaps, always convert letters to numerical positions (A=1 to Z=26) and check for uniform arithmetic differences.
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