Select the set in which the numbers are related in the same way as are the numbers of the following sets.(NOTE

Question

Select the set in which the numbers are related in the same way as are the numbers of the following sets.(NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 - Operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.)$ (23, 47, 85) $$ (11, 20, 46) $

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The correct answer is Option B: $(17, 6, 38)$. Identify the relation: The third number is (First × 2) + (Second × 1) is too simple; instead look for (First + Second) × constant or (First + Second) = Third/Constant. Actually, the pattern is: (First + Second) × 2 = Third. E.g., (23+47)×2 = 70×2 = 140 (X); let's re-verify: (23+47) = 70, (85-70) = 15; (11+20) = 31, (46-31) = 15. The pattern is (First + Second) + 15 = Third.

Step-by-Step Solution & Concepts:
Shortcut Trick: Identify the relation: The third number is (First × 2) + (Second × 1) is too simple; instead look for (First + Second) × constant or (First + Second) = Third/Constant. Actually, the pattern is: (First + Second) × 2 = Third. E.g., (23+47)×2 = 70×2 = 140 (X); let's re-verify: (23+47) = 70, (85-70) = 15; (11+20) = 31, (46-31) = 15. The pattern is (First + Second) + 15 = Third.

Steps: Analyze the pattern: Observe the first set (23, 47, 85): 23 + 47 = 70. Then, 85 - 70 = 15. The pattern is (Term 1 + Term 2) + 15 = Term 3.. Verify with the second set: Observe the second set (11, 20, 46): 11 + 20 = 31. Then, 31 + 15 = 46. The pattern is consistent.. Apply to options: Check Option B: (17, 6, 38). (17 + 6) = 23. Adding 15 results in 23 + 15 = 38. This matches the third number exactly.

Answer: B is correct because the sequence follows the rule (First + Second) + 15 = Third, and (17 + 6) + 15 = 38.

Why options are wrong: A: (9, 16, 42) -> 9+16=25, 25+15=40 != 42. C: (8, 7, 35) -> 8+7=15, 15+15=30 != 35. D: (21, 15, 50) -> 21+15=36, 36+15=51 != 50.

Exam Tip: If multiple operations seem possible, calculate the differences between the expected outcome and the sum of the first two numbers; constant differences are common in competitive exams.

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