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The ratio of the present ages of Manmohan and his wife Manpreet is 7:6. After 6 years, the ratio of their ages will be 8:7. If at the time of marriage, the ratio of their ages was 4:3, then how many years ago from now did they get married?
13 years
18 years
16 years
15 years
18 years
Observe the constant difference in ratios: the ratio increases from 7:6 to 8:7 (an increase of 1 unit in 6 years). Therefore, 1 ratio unit = 6 years. Present ages are 42 and 36. At 4:3 ratio, the ages were 24 and 18, which happened 18 years ago.
Present ratio of Manmohan and Manpreet is 7:6. Ratio after 6 years is 8:7. Marriage age ratio was 4:3.
Age┬аRatio=W+tM+tтАЛ=baтАЛ
Observe the constant difference in ratios: the ratio increases from 7:6 to 8:7 (an increase of 1 unit in 6 years). Therefore, 1 ratio unit = 6 years. Present ages are 42 and 36. At 4:3 ratio, the ages were 24 and 18, which happened 18 years ago.
Students often forget to calculate the number of years 'ago' by subtracting the past age from the present age, instead calculating only the past age.
Calculate present ages
Let present ages be 7x and 6x. After 6 years, their ages are 7x+6 and 6x+6. Given the ratio is 8:7: (7x+6)/(6x+6)=8/7
49x+42=48x+48тЯ╣x=6
Determine current ages
Substituting x=6, Manmohan's age is 7├Ч6=42 and Manpreet's age is 6├Ч6=36.
M=42,W=36
Calculate years passed since marriage
Let marriage be y years ago. Ages were (42тИТy) and (36тИТy) with ratio 4:3: (42тИТy)/(36тИТy)=4/3
126тИТ3y=144тИТ4yтЯ╣y=18
B is correct because the calculation of the past age ratio 4:3 indicates that the marriage took place 18 years ago.
This method of finding constant gaps in ratios is highly applicable to 'Train' and 'Work-Time' problems where a consistent rate of change is observed.
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