Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
The sum of three consecutive multiples of 6 is 3240, find the smallest one.
1054
1074
1006
1086
1074
Divide the sum by 3 to find the middle number: 3240/3=1080. Since the numbers are consecutive multiples of 6, subtract 6 from 1080 to find the smallest number: 1080тИТ6=1074.
Sum of three consecutive multiples of 6 is 3240.
x+(x+6)+(x+12)=3240
Divide the sum by 3 to find the middle number: 3240/3=1080. Since the numbers are consecutive multiples of 6, subtract 6 from 1080 to find the smallest number: 1080тИТ6=1074.
Students often use the expression (xтИТ6)+x+(x+6) but forget that 'smallest' refers to xтИТ6, or they mistakenly use x+(x+1)+(x+2)=3240 ignoring the 'multiple of 6' constraint.
Define the terms
Let the three consecutive multiples of 6 be x, x+6, and x+12.
x,x+6,x+12
Set up the equation
The sum of these three terms is 3240, so set up the equation accordingly.
x+(x+6)+(x+12)=3240
Solve for x
Simplify the expression: 3x+18=3240. Subtract 18 from both sides: 3x=3222. Divide by 3: x=1074.
x=1074
Identify the smallest multiple
Since x is the smallest term, the smallest multiple is 1074.
1074
B is correct because the average of three consecutive multiples of 6 is the middle term, 3240/3=1080, and subtracting 6 gives the smallest term 1080тИТ6=1074.
This logic of finding the 'average' (middle term) is highly effective for any sequence of numbers in arithmetic progression, saving time in competitive exams.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants