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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
EI-MH
PT-XR
GK-OJ
NR-VQ
PT-XR
Calculate the difference between the alphabetical positions of the letters in each pair. The odd one is the pair where the logic of differences between 1st-2nd and 3rd-4th letters does not match.
Calculate the difference between the alphabetical positions of the letters in each pair. The odd one is the pair where the logic of differences between 1st-2nd and 3rd-4th letters does not match.
Analyze Alphabetical Positions
Convert letters to numbers: E(5), I(9), M(13), H(8). For EI-MH: (9-5=4) and (8-13=-5).
Compare remaining pairs
GK-OJ: (11-7=4) and (10-15=-5). NR-VQ: (18-14=4) and (17-22=-5). PT-XR: (20-16=4) and (18-24=-6).
Identify the anomaly
Pairs EI-MH, GK-OJ, and NR-VQ follow the rule (+4, -5). PT-XR follows the rule (+4, -6), making it the odd one out.
A (EI-MH) follows the pattern +4, -5. C (GK-OJ) follows the pattern +4, -5. D (NR-VQ) follows the pattern +4, -5.
B is correct because PT-XR follows a different logic (+4, -6) compared to the other three pairs which follow the (+4, -5) pattern.
When faced with letter clusters in odd-one-out questions, always check the difference between adjacent letters first; 90% of these problems rely on simple arithmetic shifts.
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