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Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster does not belong to that group? (Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster)
EMS
AHO
HOV
VCJ
EMS
Calculate the difference between consecutive letters in the clusters; look for a common gap pattern.
Calculate the difference between consecutive letters in the clusters; look for a common gap pattern.
Analyze the alphabetical positions
EMS: E=5, M=13, S=19. Differences are +8 (5 to 13) and +6 (13 to 19).
Analyze AHO and HOV
AHO: A=1, H=8, O=15. Differences are +7 (1 to 8) and +7 (8 to 15). HOV: H=8, O=15, V=22. Differences are +7 (8 to 15) and +7 (15 to 22).
Analyze VCJ and conclude
VCJ: V=22, C=3 (or 29), J=10. Differences are +7 (22 to 29) and +7 (29 to 36 = 10 mod 26). AHO, HOV, and VCJ all follow a +7, +7 pattern. EMS is the odd one out because it follows a +8, +6 pattern.
B: AHO follows a +7, +7 pattern, which matches the group. C: HOV follows a +7, +7 pattern, which matches the group. D: VCJ follows a +7, +7 pattern, which matches the group.
A is correct because the letter-cluster EMS does not follow the constant gap of +7 between letters, unlike the other three options.
When faced with letter-cluster odd-one-out questions, always check the numerical difference between adjacent letters first; often the pattern is a simple arithmetic progression.
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