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Seven boxes, A, B, C, D, E, F and G, are kept one over the other but not necessarily in the same order. F is kept second from the bottom. Only three boxes are kept between F and E. D is kept at one of the positions below F. Only A is kept between E and C. B is kept at one of the positions above E. How many boxes are kept between E and D?
1
3
4
2
4
Fix the anchor (F is at position 2) then place variables based on constraints like '3 boxes between F and E'.
Fix the anchor (F is at position 2) then place variables based on constraints like '3 boxes between F and E'.
Establish the floor structure
Total 7 boxes. F is 2nd from the bottom (Position 2). Only 3 boxes are between F and E, so E must be at Position 6 (if we counted 3-4-5-6), wait: 2 + 1(3) + 1(4) + 1(5) + 1(6) = Position 6. Let's re-verify: F(2), pos 3, pos 4, pos 5, E(6). Yes, 3 boxes (3, 4, 5) between 2 and 6.
Placement of remaining boxes
Only A is kept between E and C. E is at 6. If C is at 4, A is at 5. B is above E, so B must be at 7. D is below F, only Position 1 is available. Remaining G takes position 5.
Final Sequence
Top to bottom: B(7), G(6), E(5), A(4), C(3), F(2), D(1). Boxes between E(5) and D(1) are A(4), C(3), and F(2). Total count = 3.
A: 1 is incorrect as we have 3 boxes between E and D. B: 2 is incorrect as there are 3 boxes. D: 4 is incorrect as there are only 3 boxes between E and D.
B is correct because the sequence B-G-E-A-C-F-D places E at position 5 and D at position 1, with boxes A, C, and F (total 3) kept between them.
In vertical arrangement puzzles, always fix the reference point (like '2nd from bottom') first, then map fixed relative distances to narrow down positions.
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