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Seven boxes, A, B, C, D, E, F and G, are kept one over the other but not necessarily in the same order. Only C is kept above D. Only two boxes are kept between D and F. Only G is kept below A. B is not kept immediately above F. Which box is kept fourth from the top?
B
E
D
H
E
Map out the constraints first: C > D, D _ _ F (or F _ _ D), A > G, and then verify the placement of B (B not immediately above F).
Map out the constraints first: C > D, D _ _ F (or F _ _ D), A > G, and then verify the placement of B (B not immediately above F).
Analyze Constraints
Constraints: 1) C is immediately above D (CD). 2) Two boxes between D and F (D..F or F..D). 3) G is immediately below A (AG). 4) B is not immediately above F.
Placement Logic
If we place sequence AGCD, we have 3 slots left (B, E, F). With D at 4th, F must be at 7th (to keep 2 between). Arrangement becomes A(1), G(2), C(3), D(4), E(5), B(6), F(7). Check: B is not above F? Correct, B is at 6th and F is at 7th, so B is immediately above F. Wait, rule says B is NOT immediately above F. Adjust: If B is at 5th, E is at 6th, F is at 7th. Then sequence A, G, C, D, B, E, F works perfectly.
A: Represents box A (1st), C: Represents box C (3rd), D: Represents box D (4th), E: Represents box E (5th). Box D is the correct answer.
D is correct because based on the constraints A, G, C, D, B, E, F is the valid order, placing D in the 4th position.
In stack puzzles, always prioritize the fixed constraint (like C is immediately above D) to create a block, then test empty slots.
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