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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
JN-IM
RV-QU
MQ-LO
PT-OS
MQ-LO
Calculate the alphabetical position difference between the two letters in each cluster. In three options, the difference is constant; the odd one has a different difference.
Calculate the alphabetical position difference between the two letters in each cluster. In three options, the difference is constant; the odd one has a different difference.
Analyze Cluster JN-IM
J(10) to N(14) is +4. I(9) to M(13) is +4. The pattern is (+4, +4).
Analyze Cluster RV-QU
R(18) to V(22) is +4. Q(17) to U(21) is +4. The pattern is (+4, +4).
Analyze Cluster MQ-LO
M(13) to Q(17) is +4. L(12) to O(15) is +3. The pattern is (+4, +3), which deviates.
Analyze Cluster PT-OS
P(16) to T(20) is +4. O(15) to S(19) is +4. The pattern is (+4, +4).
A: JN-IM follows the (+4, +4) difference pattern. B: RV-QU follows the (+4, +4) difference pattern. D: PT-OS follows the (+4, +4) difference pattern.
C is correct because it is the only pair that does not follow the (+4, +4) alphabetical difference pattern found in the other three pairs.
In alphanumeric coding questions where the vowel/consonant rule is excluded, check the numerical position difference between letters first as it is the most common hidden logic.