Correct Answer

Direct FormulaElectricalBasic Electrical

Option C

$E_m$

Quick Summary: Given: The instantaneous angle of the alternating EMF is theta = 90 degree.

📋 Given

The instantaneous angle of the alternating EMF is theta = 90 degree.

🔢 Formula Used

e=Emsin⁡(θ)e = E_m \sin(\theta)e=Em​sin(θ)

📊 Diagram / Illustration

🔢 Step-by-Step Solution

Identify the standard equation

The instantaneous value of an alternating EMF is given by the sinusoidal function $e = E_m \sin(\theta)$ , where $E_m$ is the peak amplitude.

e=Emsin⁡(θ)e = E_m \sin(\theta)e=Em​sin(θ)

Substitute the given angle

Substitute the given value of $\theta = 90°$ into the equation.

e=Emsin⁡(90°)e = E_m \sin(90°)e=Em​sin(90°)

Calculate the final value

Since $\sin(90°) = 1$ , the expression simplifies to $e = E_m \times 1$ .

e=Eme = E_me=Em​

✅

C is correct because at an angle of 90 degrees, the sine function reaches its maximum value of 1, making the instantaneous EMF equal to the peak EMF $E_m$ .

Core Concepts Used

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Alternating Current Sinusoidal Waveform Peak EMF

💡 EXAM TIP

This concept is fundamental to understanding phasors in electrical engineering, where the peak value ( $E_m$ ) defines the maximum potential difference in a cycle.

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