When θ is 90 degree, alternating EMF will be

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Examoogle · Accepted Answer

$E_m$

Explanation: Given: The instantaneous angle of the alternating EMF is theta = 90 degree.

Formula Used: $$e = E_m \sin(	heta)$$

Steps: Identify the standard equation: The instantaneous value of an alternating EMF is given by the sinusoidal function $e = E_m \sin(	heta)$, where $E_m$ is the peak amplitude.. Substitute the given angle: Substitute the given value of $	heta = 90^\circ$ into the equation.. Calculate the final value: Since $\sin(90^\circ) = 1$, the expression simplifies to $e = E_m 	imes 1$.

Answer: C is correct because at an angle of 90 degrees, the sine function reaches its maximum value of 1, making the instantaneous EMF equal to the peak EMF $E_m$.

Exam Tip: This concept is fundamental to understanding phasors in electrical engineering, where the peak value ($E_m$) defines the maximum potential difference in a cycle.

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