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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ElectricalPower Generation
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A three phase, 50 Hz transmission line operates at 220 kV. The line has 400 Ω surge impedance. Find the surge impedance loading

A

100 MVA

B

125 MVA

C

121 MVA

D

200 MVA

Correct Answer

Direct FormulaElectricalPower Generation
Option C

121 MVA

Quick Summary: Given: Three-phase voltage V_L = 220 kV, Surge impedance Z_c = 400 Ω, Frequency f = 50 Hz

📋 Given

Three-phase voltage VLV_{L}VL​ = 220 kV, Surge impedance ZcZ_{c}Zc​ = 400 Ω, Frequency f = 50 Hz

🔢 Formula Used

SIL=VL2ZcSIL = \frac{V_L^2}{Z_c}SIL=Zc​VL2​​

🔢 Step-by-Step Solution
1

Identify the formula for Surge Impedance Loading

The Surge Impedance Loading (SIL) of a transmission line is defined by the square of the line voltage divided by its surge impedance.

SIL=VL2ZcSIL = \frac{V_L^2}{Z_c}SIL=Zc​VL2​​

2

Substitute given values

Given VL=220 kV=220×10°3 VV_L = 220 \text{ kV} = 220 \times 10°3 \text{ V}VL​=220 kV=220×10°3 V and Zc=400Z_c = 400Zc​=400 Ω\OmegaΩ.

SIL=(220×10°3)2400SIL = \frac{(220 \times 10°3)^2}{400}SIL=400(220×10°3)2​

3

Calculate the result

Squaring the voltage gives 48400×10°648400 \times 10°648400×10°6. Dividing by 400400400 results in 121×10°6 VA121 \times 10°6 \text{ VA}121×10°6 VA.

SIL=48400×10°6400=121×10°6 VA=121 MVASIL = \frac{48400 \times 10°6}{400} = 121 \times 10°6 \text{ VA} = 121 \text{ MVA}SIL=40048400×10°6​=121×10°6 VA=121 MVA

✅

C is correct because the calculated surge impedance loading for the given parameters is 121 MVA.

Core Concepts Used
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Surge Impedance Loading Transmission Line Characteristics Power System Analysis
💡 EXAM TIP

SIL is independent of the line length and frequency, and it represents the load at which the line absorbs as much reactive power as it generates.

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