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D, R, A, W and S have different marks. Only one person has scored between A and R. Only one person has scored between R and W. S has scored more than R and W. How many people have scored less than D?
One
Two
Four
Three
One
Map the relative positions of A, R, W first, then place S above R/W to define the upper half, leaving D to satisfy the gap constraints.
Map the relative positions of A, R, W first, then place S above R/W to define the upper half, leaving D to satisfy the gap constraints.
Establish the ARW sequence
Given only one person between A and R, and only one between R and W, the sequence must be A-R-W or W-R-A.
Integrate S and D
S > R and S > W. Placing S at the top, the sequence becomes S, A, R, D, W (or S, D, A, R, W). Testing the constraint 'one between A and R' and 'one between R and W', the order S > A > R > D > W satisfies all conditions: A to R has 0 distance, R to W has D between them. This confirms D is 4th in a 5-person sequence.
Verify D's position
In the arrangement S > A > R > D > W, D has only 1 person (W) scoring less than D.
B: Two people cannot score less than D as it violates the specific gap requirements for A, R, and W. C: Four people would imply D is last, which conflicts with W being the lowest in the set. D: Three people would place D in the middle of the upper hierarchy, failing to accommodate the R-W gap requirement.
A is correct because the only arrangement satisfying all constraints (S > A > R > D > W) places only W below D, meaning exactly one person scored less than D.
In ranking puzzles, always place the anchor elements (R and W) first, then fill the gaps with the remaining variables while checking the relative 'greater than' conditions.
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