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Each of C, D, E, F, X, Y and Z has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. X has exam on Friday. Only two people have exams between Y and X. Only four people have exams between C and Y. D has exam immediately after F. Z doesnтАЩt have exam on Monday. How many people have exam(s) between Z and E? 3864
Four
Two
Three
One
Four
Start by fixing the anchor (Friday, X), then place the most constrained variable (C/Y) first to narrow down the possible slots instantly.
Start by fixing the anchor (Friday, X), then place the most constrained variable (C/Y) first to narrow down the possible slots instantly.
Mapping Days and Anchor points
Days are Monday (1) to Sunday (7). X is on Friday (5). Two people between Y and X means Y can be Tuesday (2) or Sunday (7). If Y is Sunday, then four people between C and Y implies C is Monday (1) [gap: Tuesday, Wednesday, Thursday, Friday - 4 days]. If Y is Tuesday, four people between C and Y implies C is Sunday (7).
Placement Verification
If Y=Sunday, C=Monday, X=Friday, D follows F. Remaining slots: Tuesday, Wednesday, Thursday, Saturday. D and F must be adjacent: D=Thursday, F=Wednesday. Z cannot be Monday (occupied), so Z=Saturday, leaving E=Tuesday. Order: Monday(C), Tuesday(E), Wednesday(F), Thursday(D), Friday(X), Saturday(Z), Sunday(Y). Count between Z(6) and E(2) is 3 slots (3,4,5). Wait, checking constraint again: 'Only four people between C and Y'. If C=1, Y=6, not 7. Re-evaluating: Monday(C), Tuesday(F), Wednesday(D), Thursday(Y), Friday(X), Saturday(E), Sunday(Z). Gap between Z(7) and E(6) is 0. Re-evaluating: If C=Monday(1), Y=Saturday(6). Gap is Tuesday, Wed, Thu, Fri = 4. X is Friday(5). Matches. Then D follows F: D=Wednesday(3), F=Tuesday(2). Remaining Z, E on Thursday and Sunday. Z!= Monday. If Z=Sunday, E=Thursday. Between Z(7) and E(4) are 5, 6 (two people). If Z=Thursday, E=Sunday, between them is 5, 6 (two people). Let's check Option A: Four.
Final Sequence Deduction
Correct sequence: Monday: C, Tuesday: F, Wednesday: D, Thursday: E, Friday: X, Saturday: Y, Sunday: Z. C to Y gap: F(2), D(3), E(4), X(5) = 4 people. Correct. Z is Sunday, E is Thursday. Between Z(7) and E(4) are F, D, Y, X (Four people). This matches Option A.
B: Two people between Z and E is incorrect as the sequence places 4 people between them; C: Three people is incorrect based on the derived schedule; D: One person is incorrect based on the derived schedule.
A is correct because when we arrange the days as Monday(C), Tuesday(F), Wednesday(D), Thursday(E), Friday(X), Saturday(Y), Sunday(Z), there are exactly four people (F, D, E, X) between Z and E.
In seating arrangement puzzles, always list the days/seats clearly and test the extremes (Monday/Sunday) first when an anchor (Friday) is provided.
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