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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ElectricalBasic Electrical
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If voltage drop across capcitor is 100V and current is 5A, what is value of capacitive reactance?

A

10Ω10\Omega10Ω

B

20Ω20\Omega20Ω

C

30Ω30\Omega30Ω

D

40Ω40\Omega40Ω

Correct Answer

Concept & PrincipleElectricalBasic Electrical
Option B

20Ω20\Omega20Ω

Quick Summary: Capacitive reactance ($X_C$) is the opposition offered by a capacitor to the flow of alternating current. It is determined by the ratio of the RMS voltage drop across the capacitor ($V_C$) to the RMS current flowing through it ($I_C$), expressed as $X_C = \frac{V_C}{I_C}$.

💡 Explanation

Capacitive reactance (XCX_CXC​) is the opposition offered by a capacitor to the flow of alternating current. It is determined by the ratio of the RMS voltage drop across the capacitor (VCV_CVC​) to the RMS current flowing through it (ICI_CIC​), expressed as XC=VCICX_C = \frac{V_C}{I_C}XC​=IC​VC​​.

🔢 Key Formulas

XC=VIX_C = \frac{V}{I}XC​=IV​ — Formula to calculate capacitive reactance when voltage and current are known.

XC=12πfCX_C = \frac{1}{2\pi f C}XC​=2πfC1​ — Fundamental formula relating reactance to frequency and capacitance.

⚙️ Working Principle

In an AC circuit, a capacitor stores and releases charge continuously as the voltage changes. This charging and discharging process results in a current that leads the voltage by 90 degrees. The opposition to this current flow, known as capacitive reactance, is inversely proportional to both the frequency of the supply and the capacitance of the component.

📌 Key Points
  • ▸

    Capacitive reactance is measured in Ohms (Ω).

  • ▸

    It causes a phase shift where current leads voltage by 90°90°90°.

  • ▸

    Reactance decreases as frequency increases.

  • ▸

    For the given values, XC=100V5A=20ΩX_C = \frac{100V}{5A} = 20\OmegaXC​=5A100V​=20Ω.

✅ Advantages
  • ▸

    Used in AC filters to block DC.

  • ▸

    Essential for phase shifting in motors.

❌ Disadvantages / Limitations
  • ▸

    Reactance is frequency dependent, making it unstable in wide-band circuits.

  • ▸

    Pure capacitors do not dissipate real power.

🛠️ Applications / Uses
  • ▸

    Coupling capacitors in amplifiers.

  • ▸

    Power factor correction units.

📄 Additional Information
  • ▸

    The calculation is XC=1005=20ΩX_C = \frac{100}{5} = 20\OmegaXC​=5100​=20Ω.

  • ▸

    Options A, C, and D are incorrect calculations based on the provided parameters.

📊 Diagram / Illustration
Capacitive ReactanceVoltage (V)Current (I)
✅

B is correct — Using Ohm's law for AC circuits, XC=VI=1005=20ΩX_C = \frac{V}{I} = \frac{100}{5} = 20\OmegaXC​=IV​=5100​=20Ω.

Core Concepts Used
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Capacitive Reactance Ohm's Law for AC Phase Relationship
💡 EXAM TIP

Always remember that in an AC circuit with a capacitor, current leads the voltage. The reactance value XCX_CXC​ must always be treated as a negative imaginary component in complex impedance calculations (−jXC-jX_C−jXC​).

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