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Resistance is 50 ohm and voltage is 200V in series resonance, what is value of current?
1A
2A
3A
4A
4A
Quick Summary: Given: Resistance R = 50 ohm, Voltage V = 200V. The circuit is in series resonance.
Resistance R = 50 ohm, Voltage V = 200V. The circuit is in series resonance.
I=ZVтАЛ
Understand Series Resonance Condition
In an RLC series resonance circuit, the inductive reactance (XLтАЛ) and capacitive reactance (XCтАЛ) cancel each other out, such that the net reactance is zero (XLтАЛтИТXCтАЛ=0).
Z=R+j(XLтАЛтИТXCтАЛ)=R
Identify Impedance
At resonance, the total impedance (Z) of the circuit is equal to the resistance (R). Given R=50╬й, the impedance is 50╬й.
Z=50╬й
Calculate Current
Using Ohm's Law for AC circuits at resonance, divide the source voltage by the resistance.
I=50200тАЛ=4A
D is correct because at series resonance, the total impedance is purely resistive (Z=R), leading to a current of I=200V/50╬й=4A.
Always remember that at resonance, the power factor of a series RLC circuit is unity because the circuit behaves purely as a resistor.