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ElectricalBasic Electrical
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Resistance is 50 ohm and voltage is 200V in series resonance, what is value of current?

A

1A

B

2A

C

3A

D

4A

Correct Answer

Direct FormulaElectricalBasic Electrical
Option D

4A

Quick Summary: Given: Resistance R = 50 ohm, Voltage V = 200V. The circuit is in series resonance.

ЁЯУЛ Given

Resistance R = 50 ohm, Voltage V = 200V. The circuit is in series resonance.

ЁЯФв Formula Used

I=VZI = \frac{V}{Z}I=ZVтАЛ

ЁЯФв Step-by-Step Solution
1

Understand Series Resonance Condition

In an RLC series resonance circuit, the inductive reactance (XLX_LXLтАЛ) and capacitive reactance (XCX_CXCтАЛ) cancel each other out, such that the net reactance is zero (XLтИТXC=0X_L - X_C = 0XLтАЛтИТXCтАЛ=0).

Z=R+j(XLтИТXC)=RZ = R + j(X_L - X_C) = RZ=R+j(XLтАЛтИТXCтАЛ)=R

2

Identify Impedance

At resonance, the total impedance (ZZZ) of the circuit is equal to the resistance (RRR). Given R=50╬йR = 50 \OmegaR=50╬й, the impedance is 50╬й50 \Omega50╬й.

Z=50╬йZ = 50 \OmegaZ=50╬й

3

Calculate Current

Using Ohm's Law for AC circuits at resonance, divide the source voltage by the resistance.

I=20050=4AI = \frac{200}{50} = 4AI=50200тАЛ=4A

тЬЕ

D is correct because at series resonance, the total impedance is purely resistive (Z=RZ=RZ=R), leading to a current of I=200V/50╬й=4AI = 200V / 50\Omega = 4AI=200V/50╬й=4A.

Core Concepts Used
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Series Resonance Impedance in RLC circuits Ohm's Law
ЁЯТб EXAM TIP

Always remember that at resonance, the power factor of a series RLC circuit is unity because the circuit behaves purely as a resistor.

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