Join 60,000+ competitive exam aspirants
Refer to the given series and answer the question that follows (all numbers are single-digit numbers only).
What is the sum of the 3ʳᵈ digit from the left and the 3ʳᵈ digit from the right?
9
12
11
10
11
Count positions from each end, ignoring the instructions if they are meant to be 'single-digit numbers', and locate the specific digits.
Count positions from each end, ignoring the instructions if they are meant to be 'single-digit numbers', and locate the specific digits.
Identify 3rd digit from left
In the series: 9, 3, 9, 2, 2, 1, 9, 0, 6, 0, 2, 5, 1, 0, 2, 5, 3, 8, 8, 9, 6, 5, 4, 0, 0, 6, 0, 2, 5, 3. The 1st is 9, 2nd is 3, 3rd is 9.
Identify 3rd digit from right
Counting backwards from the end (right): 1st is 3, 2nd is 5, 3rd is 2. Wait, re-counting: ...6, 0, 2, 5, 3. 1st=3, 2nd=5, 3rd=2. The original visual shows ... 6, 0, 2, 5, 3. Let us re-count carefully: 1st(3), 2nd(5), 3rd(2). Actually looking at the provided sequence: 9, 3, 9, 2, 2, 1, 9, 0, 6, 0, 2, 5, 1, 0, 2, 5, 3, 8, 8, 9, 6, 5, 4, 0, 0, 6, 0, 2, 5, 3. The last three are 2, 5, 3. 3rd from right is 2. Sum: 9+2=11.
A, B, D are incorrect based on the verified positional counts from the provided string: 3rd from left (9) + 3rd from right (2) = 11.
C is correct because the 3rd digit from the left is 9 and the 3rd digit from the right is 2, and their sum 9 + 2 = 11.
Always double-check the counting direction; 'from right' means starting from the last element and moving leftwards.