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Refer to the given series and answer the question that follows (all numbers are single-digit numbers only, and all counting is to be done from left to right).
How many such even digits are there, each of which is immediately preceded by an even digit and also immediately followed by an odd digit?
3
0
2
1
2
Look for a cluster of three digits where the sequence is [Even, Even, Odd]. Scan left to right and strike off each match.
Look for a cluster of three digits where the sequence is [Even, Even, Odd]. Scan left to right and strike off each match.
Define the criteria
The condition is: Even digit preceded by an even digit AND followed by an odd digit. This effectively means looking for a triplet pattern: (Even, Even, Odd).
Scan the sequence
The series is: 5, 7, 8, 9, 6, 7, 7, 5, 8, 9, 2, 5, 5, 9, 5, 5, 9, 5, 4, 6, 7, 2, 8, 3, 5, 8, 3, 9, 7, 9.
Identify matches
1) 8-6-7: 8(E), 6(E), 7(O). Match found. 2) 4-6-7: 4(E), 6(E), 7(O). Match found. 3) 2-8-3: 2(E), 8(E), 3(O). Match found. No other sequences satisfy this pattern.
A: Incorrect, as there are 3 instances. B: Incorrect, there are exactly 3, not 2. D: Incorrect, there are not 4 instances.
C is correct because the sequence contains exactly three occurrences of the Even-Even-Odd pattern: 8-6-7, 4-6-7, and 2-8-3.
When counting patterns in long strings, use a pencil to underline identified sets to avoid double-counting or missing overlaps.
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