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Refer to the given series and answer the question that follows (all numbers are single-digit numbers only).
What is the sum of the $ 15^{th}$ digit from the left and the $ 11^{th}$ digit from the right?
13
11
14
16
13
Count carefully from the respective ends: 15th from the left is the 15th digit, and 11th from the right is the (Total-11+1)th position from the left.
Count carefully from the respective ends: 15th from the left is the 15th digit, and 11th from the right is the (Total-11+1)th position from the left.
List the series
5, 1, 3, 3, 0, 6, 0, 2, 9, 1, 8, 4, 2, 2, 5, 4, 6, 8, 5, 8, 1, 3, 5, 0, 2, 1, 3, 9, 5, 4 (Total 30 digits).
Find the 15th digit from the left
Counting from the left (1:5, 2:1, 3:3, 4:3, 5:0, 6:6, 7:0, 8:2, 9:9, 10:1, 11:8, 12:4, 13:2, 14:2, 15:5). The 15th digit is 5.
Find the 11th digit from the right
The 11th digit from the right is the (30 - 11 + 1) = 20th digit from the left. Counting: 16:4, 17:6, 18:8, 19:5, 20:8. The 11th digit from the right is 8.
Calculate the sum
Sum = 5 + 8 = 13.
B: 11 is incorrect as it is not the sum; C: 14 is incorrect; D: 16 is incorrect.
A is correct because the 15th digit from the left is 5 and the 11th digit from the right is 8, and their sum is 5 + 8 = 13.
In long series questions, always count the total number of elements first to quickly convert 'from right' positions to 'from left' positions using the formula: PositionLeft = Total - PositionRight + 1.
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